The Content on “ZenHealthTips” constitutes furnished as general information only, All information provided within this internet site is in no way intended to be a substitute for professional medical advice.You should not use this information to diagnose or treat a health problem or disease without consulting with a qualified healthcare provider. it  should not be treated as a substitute for the medical advice of your own doctor, psychiatrist or any other health care professional. Consult your health care provider on any doubts or concerns you may have regarding your condition.

We are not responsible or liable for any diagnosis, decision or self-assessment made by a user based on the content of this website. Always consult your own General Physician if you’re in any way concerned about your health.